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The Roswell Report: Fact vs. Fiction in the New Mexico Desert

USAF / The Black Vault · 1995 · 882 pages · text by OCR

The Roswell Report: Fact versus Fiction in the New Mexico Desert was published by Headquarters United States Air Force in 1995. The Black Vault distributes this copy. It reproduces the report by Col. Richard L. Weaver and the synopsis by 1st Lt. James McAndrew, both written after a General Accounting Office inquiry requested by Representative Steven Schiff. The Air Force search found no evidence of an extraterrestrial craft or crew. It concluded that the Roswell debris most likely came from NYU Flight No. 4, a Project MOGUL balloon train.

  • p. 193 …overhead and followed the balloons out to sea. I have no idea about the results that…
  • p. 200 …the regular 334 that we had at sea level. From that they could deduce the temperature…
  • p. 243 …actually located on the jurisdictional lines between Sea Girt and Springlake, New Jersey. It was an…
  • p. 244 …The Sea Girt Inn? A: Exactly. That's where John had his office, and I was…
  • p. 320 …alone is about 24,000 miles at sea level, and about 4500 miles at 45,000…
  • p. 325 …twenty-five (25) feet at their largest sea-level diameter. The sonic unit was a combination…
  • p. 378 …per hour when one-fifth inflated at sea level). One other type of balloon which has…
  • p. 402 …Let us, then, compare the rate of leakage at any given altitude with leakage at sea…
  • p. 404 …The leakage at any altitude may be expressed as a function of leakage at sea level…
  • p. 405 Comparing rate of leakage at 40,000 feet with leakage at sea level: $$ \frac {L _ {4…
  • p. 407 …If a 20-foot diameter balloon $ \frac{1}{1 0} $ full were tested at sea level…
  • p. 408 …At sea level this is equivalent to 5.32 gm/hr. for a 20-foot diameter…
  • p. 414 …Using the rules of subsonic aerodynamics, Picard suggests that air at sea level escaping at 1333…
  • p. 415 …air at sea level (lb./ft. $ ^{3} $ ) 14.7 = pressure of air at sea level (psi…
  • p. 432 …to about 20 millibars and increased to sea-level pressure at different temperatures. The most comprehensive…
  • p. 563 …The height above mean sea level as determined from pressure measurements used in this work with…
  • p. 644 …point at which the radiosonde reaches the sea surface. ## 2. Earlier attempts There have been numerous…
  • p. 645 …The balloons floated between the surface and 30,000 ft above sea level; those which reached…
  • p. 704 …Met Gifford who has 90' sea rescue boat this project is planning to use. Stayed at…
  • p. 719 …Worzel working on gravity at sea. Saw Geo Woollard and the Ryders. Woollard after Guggenheim fellowship…
  • p. 779 …the launching site is markedly different from sea level, a shift in this curve is needed…
  • p. 817 …balloon at all times with respect to sea level. On this curve also it is customary…
  • p. 825 …The height above mean sea level as determined from pressure measurements used in this work with…
the pressure distribution of the lifting gas and the internal back pressure due to valving gas. To find maximum rates of ascent for various balloons would necessitate a complicated series of trial and error solution. In general, it has been more practical to determine a maximum rate of rise for normal operating conditions for any given size balloon by finding the maximum allowable rate for the balloon rising to its lowest normal operating level (i.e., we will find the maximum allowable rate for the worst normal operating conditions and consider it a maximum for all normal operating conditions.)

Let us take the case of a 20-foot diameter polyethylene balloon of .001" thickness. Lowest normal floating altitude is 20,000 ft. MSL. Let us assume that the balloon will be full and begin valving gas at 15,000 ft. MSL. Assume the appendix diameter to be $ \frac{1}{2} $ foot. Using equation (1) to find maximum allowable internal pressure and assuming the critical x-y plane to be that of maximum diameter $ \Delta Z=D/2 $ , we have:

$$
\Delta p _ {\mathrm {a l l .}} = \frac {4 S _ {\mathrm {f t}}}{D} = \frac {4 (9 0 0 / 2) \cdot . 0 0 1}{1 2 \cdot 2 0} = . 0 0 7 5 \mathrm {p s i}
$$

(Here we have introduced a factor of safety by saying $ S_{f}=9 0 0 / 2 $ instead of 900 psi, the ultimate strength in tension of polyethylene.) Pressure distribution:

$$
\Delta p _ {D / 2} = \Delta z \frac {d p}{d z} (1 - B) = \frac {\angle O}{2} \cdot 3. 3 8 \cdot 1 0 ^ {- 4} \cdot 8 6 2 = . 0 0 2 9 1 p s i
$$

Allowable back pressure:

$$
\Delta p _ {b p} = \Delta p _ {a l l} - \Delta p _ {0 / 2} = . 0 0 4 6 \mathrm {p s i}
$$

Maximum rate of rise using equation (13);

$$
\frac {d Z}{d t} = \sqrt {\frac {2 8 8 \Delta p _ {b p} g}{d _ {g}}} \left(\frac {2 7 8 0 0}{V} C _ {d} A _ {a}\right) f t / \sec
$$

$$
= 1 0 0. 7 \mathrm {f t / s e c}
$$

$$
= 6 0 0 0 \mathrm {f t / m i n}
$$

It is evident from this calculation that the rate of rise of the 20-ft. diameter polyethylene balloon is not a critical factor in bursting unless the open appendix becomes snarled and gas is not allowed to escape.

Rate of rise and appendix openings are important from the standpoint of balloon design. For operational reasons it is important to have a rapid rate of rise. In order to make most efficient use of weight, the balloon film should be thin. As mentioned

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Report, cited by the archive. The PDF is mirrored here; the original link is under it. The text was read from the page images by an OCR model; expect the odd misread word. 882 pages are in the text index: search them above, or from the library's search.