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The Roswell Report: Fact vs. Fiction in the New Mexico Desert

USAF / The Black Vault · 1995 · 882 pages · text by OCR

The Roswell Report: Fact versus Fiction in the New Mexico Desert was published by Headquarters United States Air Force in 1995. The Black Vault distributes this copy. It reproduces the report by Col. Richard L. Weaver and the synopsis by 1st Lt. James McAndrew, both written after a General Accounting Office inquiry requested by Representative Steven Schiff. The Air Force search found no evidence of an extraterrestrial craft or crew. It concluded that the Roswell debris most likely came from NYU Flight No. 4, a Project MOGUL balloon train.

  • p. 193 …overhead and followed the balloons out to sea. I have no idea about the results that…
  • p. 200 …the regular 334 that we had at sea level. From that they could deduce the temperature…
  • p. 243 …actually located on the jurisdictional lines between Sea Girt and Springlake, New Jersey. It was an…
  • p. 244 …The Sea Girt Inn? A: Exactly. That's where John had his office, and I was…
  • p. 320 …alone is about 24,000 miles at sea level, and about 4500 miles at 45,000…
  • p. 325 …twenty-five (25) feet at their largest sea-level diameter. The sonic unit was a combination…
  • p. 378 …per hour when one-fifth inflated at sea level). One other type of balloon which has…
  • p. 402 …Let us, then, compare the rate of leakage at any given altitude with leakage at sea…
  • p. 404 …The leakage at any altitude may be expressed as a function of leakage at sea level…
  • p. 405 Comparing rate of leakage at 40,000 feet with leakage at sea level: $$ \frac {L _ {4…
  • p. 407 …If a 20-foot diameter balloon $ \frac{1}{1 0} $ full were tested at sea level…
  • p. 408 …At sea level this is equivalent to 5.32 gm/hr. for a 20-foot diameter…
  • p. 414 …Using the rules of subsonic aerodynamics, Picard suggests that air at sea level escaping at 1333…
  • p. 415 …air at sea level (lb./ft. $ ^{3} $ ) 14.7 = pressure of air at sea level (psi…
  • p. 432 …to about 20 millibars and increased to sea-level pressure at different temperatures. The most comprehensive…
  • p. 563 …The height above mean sea level as determined from pressure measurements used in this work with…
  • p. 644 …point at which the radiosonde reaches the sea surface. ## 2. Earlier attempts There have been numerous…
  • p. 645 …The balloons floated between the surface and 30,000 ft above sea level; those which reached…
  • p. 704 …Met Gifford who has 90' sea rescue boat this project is planning to use. Stayed at…
  • p. 719 …Worzel working on gravity at sea. Saw Geo Woollard and the Ryders. Woollard after Guggenheim fellowship…
  • p. 779 …the launching site is markedly different from sea level, a shift in this curve is needed…
  • p. 817 …balloon at all times with respect to sea level. On this curve also it is customary…
  • p. 825 …The height above mean sea level as determined from pressure measurements used in this work with…
of the surrounding atmosphere. Upon reaching the altitude at which it is full it will still have an unbalance in the direction of increase of altitude due to the excess buoyancy causing ascent. This unbalance is gradually decreased as the balloon rises (with a fixed volume) into less dense air. Meanwhile excess gas pressure is relieved by valving gas through the appendix until the balloon system is in a condition of equilibrium. The portion of the ascent after the balloon has become full is known as the "leveling-off" period.

The lifting gas which is valved out through the appendix will cause a "back pressure" inside of the balloon which must be transferred to the balloon fabric or film. In other words, there must be a pressure difference across the appendix opening during this period to force the excess lifting gas out of the balloon. Let us analyze this back pressure by the method used by Picard. Using the rules of subsonic aerodynamics, Picard suggests that air at sea level escaping at 1333 ft/sec. produces a back pressure of 1 atmosphere and that back pressure induced is proportional to the square of escape velocity of the gas and inversely proportional to the density of the gas escaping. Volume of gas lost in ascent through 1 foot is, within a reasonable degree of accuracy:

(6)

$$
\frac {\Delta V}{\Delta z} = \frac {V}{P} \frac {d p}{d z} \cdot \frac {T + \Delta T}{T}
$$

$ \frac{\Delta V}{\Delta Z}=\mathrm{volume~lost~per~foot~of~ascent~(ft.^{3}/ft.)} $

V = balloon volume (ft. $ ^{3} $ )

P = pressure of free air (psi)

$ \frac{dp}{dz} = $ pressure change with increase of Z (psi/ft)

T = temperature of air ( $ ^{\circ} \mathrm{C} $ abs. )

$ \Delta T= $ change in air temperature during rise ( $ ^{\circ} \mathrm{C} $ )

For ascent in the troposphere this relationship will reduce to:

$$
\frac {\Delta V}{\Delta Z} = \frac {V}{2 7 , 8 0 0} \frac {F T}{F T} ^ {3}
$$

The velocity of escape of gas, then:

(8)

$$
\begin{array}{l} V = \frac {d z}{d t} \cdot \frac {V}{2 7 , 8 0 0} \cdot \frac {1}{A _ {a}} \\ V = \mathrm {v e l o c i t y o f e s c a p e o f l i f t i n g g a s (f t . / s e c .)} \\ \end{array}
$$

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Report, cited by the archive. The PDF is mirrored here; the original link is under it. The text was read from the page images by an OCR model; expect the odd misread word. 882 pages are in the text index: search them above, or from the library's search.