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The Roswell Report: Fact vs. Fiction in the New Mexico Desert

USAF / The Black Vault · 1995 · 882 pages · text by OCR

The Roswell Report: Fact versus Fiction in the New Mexico Desert was published by Headquarters United States Air Force in 1995. The Black Vault distributes this copy. It reproduces the report by Col. Richard L. Weaver and the synopsis by 1st Lt. James McAndrew, both written after a General Accounting Office inquiry requested by Representative Steven Schiff. The Air Force search found no evidence of an extraterrestrial craft or crew. It concluded that the Roswell debris most likely came from NYU Flight No. 4, a Project MOGUL balloon train.

  • p. 118 …Robert Gross and Mr. Maher of Lockheed 11:55 A.M. Gen. Sam Anderson 12:00…
  • p. 393 …in the form of an altitude vs. gross load chart with helium as the lifting gas…
  • p. 394 …4}{\text {Gross Load}} = \frac {K}{W} $$ In turn, $ \frac{K}{W}=a e^{-0. 4…
  • p. 395 …free lift in pounds and G is gross lift in pounds. Although this equation was derived…
  • p. 400 …By equation (10), with a gross load of 52 kg., the unbalance caused by loss of…
  • p. 412 …or a gross buoyancy of 450 lb., the maximum allowable inflation of a 30' diameter, .001…
  • p. 479 …accelerating force equal to 5% of the gross load (52 kg) was acting to bring the…
  • p. 552 …000 feet. In one step, this becomes: Gross Lift/Balloon = (Balloon Volume) x (Difference in molecular…
  • p. 555 …of rise in feet per minute G = gross lift in grams For our purposes, we wish…
  • p. 559 …G) ^ {\frac {2}{3}} $$ (Approximate) where G = gross load A chart, Figure 24, has beendrawn up…
  • p. 561 …where $ \triangle G= $ loss of lift G = gross load (balloon weight plus equipment load) $ \triangle T…
  • p. 562 …not including balloon or its integral parts. Gross load: Load on the gas at release (Balloon…
  • p. 635 …Serial No. ___ description ___ ___ Line length ___ Banner description ___ ___ Ballast assembly - description ___ ___ Eallast. ___ Total Equipment Weight. ___ Gross Load ___
  • p. 636 …Gross Load . . . ___ Assumed Gross Lift (Gross Load + 10%) G ___ G 2/3 ___ Free Lift - F = $ (\frac…
  • p. 649 …theoretical altitude determined by the displacement and gross load. ## 7. Control systems Two systems of control…
  • p. 681 …By adjusting the gross load to be supported by the gas to equal the total lift…
  • p. 691 …A chart showing the relation between altitude, gross lift, and balloon size has been found necessary…
  • p. 775 …The gross load reported should be accurate to the nearest 200 grams. The amount of lifting…
  • p. 777 500 gm DRAG CHUTES 300 " BANNER 2000 " PAYLOAD 4500 " BALLOON 7300 " GROSS LOAD ## NOTE: Use low…
  • p. 779 …bubble length and resultant inflated volume, using gross lift as an expression of volume. It will…
  • p. 781 …in Appendix II summarizes the relationship between gross load and floating level for balloons of several…
  • p. 817 …A can of sand is made to weigh the same amount as the required gross lift…
  • p. 825 …the balloon with the equipment load attached. Gross Lift: Lift of all of the gas in…
  • p. 830 …Serial No. ___ description ___ Drag chute ___ ___ Banner description ___ ___ Ballast assembly - description ___ ___ Ballast ___ Total Equipment Weight . ___ Gross Load . . . . . . . . . . . . . . . . ___
  • p. 831 …waiting___ grams Actual balloon lift . . . . . . . . . . . ___ " AActual gross lift (Balloon lift & balloon wt.) . . . . . ___ " Number Helium tanks required…
  • p. 835 …Gross Lift vs. Bubble Length . . . . . . . 107 Graph 3: Buoyancy vs. Altitude . . . . . . . . . . 108 Graph 4: Gross Load…
  • p. 847 …Estimated Gross Load Limit kg. Altitude Range ft. 7 200 0.6 1.5 to 5…
Comparing rate of leakage at 40,000 feet with leakage at sea level:

$$
\frac {L _ {4 0}}{L _ {0}} = \sqrt {\frac {2 7}{1 1 2} \cdot \frac {1 8 8}{1 0 1 3} \cdot \frac {2 8 8}{2 1 8}} = 0. 2 4 3
$$

Comparing rate of leakage at 100,000 feet with leakage at sea level:

$$
\frac {L _ {1 0 0}}{L _ {0}} = \sqrt {\frac {2 7}{1 8 8 0} \cdot \frac {1 0 . 9}{1 0 1 3} \cdot \frac {2 8 8}{2 1 8}} = 0. 0 4 4
$$

Therefore, if leakage of a full balloon at sea level is known, it is possible to compute theoretical leakage at any altitude. However, if it is not possible to completely inflate a balloon on the ground in order to make a sea level test (if lift would be great enough to rupture balloon or load lines), a method of comparing full balloon leakage with partially full balloon leakage must be found.

Let us assume that it is possible to obtain results of a leakage test for a balloon inflated to a volume $ \frac{1}{x} $ of fullballoon volume. Again starting with equation (1):

$$
Q = C _ {d} A \sqrt {2 g h}
$$

We see that in this case the total area of openings, A is not constant but is a function of volume. Therefore, we have:

$$
Q \propto A \sqrt {h}
$$

We have shown that:

$$
h = \frac {\Delta p}{d _ {g}} \cdot 1 4 4 = \frac {\Delta z \left(\frac {d p}{d z}\right) _ {\mathrm {a i r} (1 - B)}}{d _ {g}} \cdot 1 4 4
$$

Since we are comparing partially inflated balloon leakage at sea level with full balloon leakage at sea level the variable in the above expression is $ \Delta z $ . This is graphically illustrated in Figure 24.

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Report, cited by the archive. The PDF is mirrored here; the original link is under it. The text was read from the page images by an OCR model; expect the odd misread word. 882 pages are in the text index: search them above, or from the library's search.