Documents / Analysis
The All-domain Anomaly Resolution Office of the U.S. Department of Defense issued this case resolution on the "Go Fast" video on February 6, 2025. It covers a January 2015 FLIR recording made by a U.S. Navy F/A-18F off Florida's eastern coast. From the public 34-second video, AARO puts the object at about 13,000 feet, moving at 5 to 92 mph relative to the wind. It attributes the apparent high speed to motion parallax and has high confidence the object showed no anomalous performance.
“Sea”1 page
UNCLASSIFIED 11 UNCLASSIFIED Inserting vFA18 = 190 m/s, the acceleration of gravity g = 9.81 m/s2, and θB = 14° into (6), the radius of curvature Rc was found to be 14,759 m. These values are shown in Figure 4 with the radius of curvature and position of the F/A-18 at t2. Figure 6: The F/A-18 traveled in a curved path from its position at t1 to reach its position at t2. To find yaw the angle φ at t2, note that the two φ’s in Figure 4 are equal. The total distance travelled in the partial circle by the F/A-18 moving at 190 m/s over 13 seconds is 2,470 m. Had the aircraft kept flying to complete a circle, it would have travelled 2·π·Rc or 92,736 m. Therefore, only 2.66% of a 360° circle was completed thus φ = 9.6°. Since the yaw is counterclockwise, away from the positive y-axis, it is a negative value, or φ = -9.6°. To find the F/A-18’s position at t2, the Δx and Δy change in position from the location at t1 must be found. Equations (7) and (8) use a cylindrical coordinate transformation [ref 8] to do this. ∆𝑦 = 𝑅𝑐 − 𝑅𝑐 ∙ cos(𝜑) = 14,759 ∙ (1 − cos(9.6°)) = 207 𝑚 (7) ∆𝑥 = 𝑟 ∙ sin(𝜑) = 14,759 ∙ sin(9.6°) = 2461 𝑚 (8) Thus, at t2, the aircraft’s displacement was [2,461, -207, 0] m, or 2,461 meters ahead and 207 meters left3 of its t1 position. This will be used momentarily to find the UAP’s location at t2. At t2 the UAP was at a range of 6,279 m from the F/A-18 such that the pointing vector, v2, is given by m. As with t1, the LOS vector was defined as pointed in the direction of +x-axis, not the heading of the aircraft.4 At t2 the sensor elevation and azimuth angles were β = - 35° and γ = -57°, respectively. The additional yaw of the F/A-18 of -9.6° required one additional rotation.5 The rotation by -35° about the y-axis to the sensor elevation is given in (7a-7b).6 3 The negative is applied here to conform with our coordinate system. 4 This is not the direction the F/A-18 was pointed, otherwise there would be a y-component of the vector. The additional yaw angle will be handled in the rotation matrices. 5 The sensor azimuth and F/A-18 yaw could be added and performed in a single rotation. In general, the aircraft would have roll and pitch and adding the platform angle to the sensor angle may give an incorrect result. 6 The written-out step depicting the multiplication of the matrices is skipped here.
Analysis, from the aaro collection. The PDF is mirrored here; the original link is under it. 26 pages are in the text index: search them above, or from the library's search.